Problem 1 p. 337.

Required per 1,000 lb.

5 lb Ca

4 lb P

Corn-sbm supply;

0.8 lb Ca

1.6 lb P

Still need

5 lb. - .8 lb = 4.2 lb Ca

4 lb - 1.6 lb = 3.4 lb P

To balance for these nutrients, start with P since Dical contains both P and Ca. 

3.5 lb P       = 19 lb Dical

  .18

  We divide by .18 because Dical contains 18% P or .18 P per lb of Dical.

Because Dical also contains Ca, will be adding Ca as well as P. How much Ca is contained in 19 lb of Dical.

    solution: 19 lb Dical X .23 = 4.4 lb Ca.   (.23 because there is 23% Ca in Dical).

Because we only needed 4.2 lb Ca, we have satisfied both P and Ca requirements with 19 lb of Dical; therefore limestone is not needed.

Problem 2 - fixed ingredient problem

total fixed = 10% or 10 kg/100 kg

two fixed ingredients will provide some protein... how much:

5 kg alfalfa X .20 = 1 kg CP

1 kg vit. mix X .50 = 0.5 kg CP

total CP from fixed = 1.5 kg

we want a 12% CP diet or 12 kg CP per 100 kg of diet.

we have 1.5 kg CP from fixed, so we need 10.5 kg (12-1.5) to come from milo and sbm.

set up equations:  X  =MILO; Y = SBM

      X  + Y = 90 KG (BECAUSE WE HAVE 10 KG FIXED)

.10 X + .46 Y = 10.5 KG CP

.10 X + .10 Y =   9.0 KG CP

              .36Y =    1.5

                    Y = 1.5/.36 =  4.2 OR 4 kg SBM

                    X = 85.8 or 86 kg MILO

86 kg milo

  4 kg sbm

   5 kg alfalfa

   2 kg dical

   1.5 kg limestone

     .5 kg TM salt

    1.0 kg vitamin mix

100 kg feed